How to install node.js in Windows Machine

Node.js is a popular open-source JavaScript runtime that allows developers to build server-side applications using JavaScript. In this blog post, we will go through a step-by-step guide on how to install Node.js on a Windows machine.

Step 1: Download Node.js Installer

The first step in installing Node.js on your Windows machine is to download the installer from the official website nodejs.org. You can go to the website and download the LTS version.

Step 2: Run the Installer

Once the installer has finished downloading, double-click on the installer file to run it. The installer will guide you through the installation process. You can select the "Next" button to proceed through the installation steps.

Step 3: Accept License Agreement

When you run the installer, you will be presented with a license agreement. Read through the agreement and select the "I accept the terms in the License Agreement" checkbox if you agree to the terms. Then click on the "Next" button to proceed.

Step 4: Select Destination Folder

The next step in the installation process is to select the destination folder where you want to install Node.js. You can either accept the default location or choose a custom location. Once you have selected the destination folder, click on the "Next" button to proceed.

Step 5: Choose Components

In this step, you can choose which components you want to install. By default, all components are selected. If you want to deselect any components, you can do so by unchecking the checkbox next to the component name. Once you have selected the components you want to install, click on the "Next" button to proceed.

Step 6: Install

After you have selected the components you want to install, click on the "Install" button to start the installation process. The installer will begin installing Node.js on your machine.

Step 7: Complete Installation

Once the installation process is complete, you will see a "Completed" message. Click on the "Finish" button to close the installer.

Step 8: Verify Installation

To verify that Node.js has been installed successfully, open a command prompt and type "node -v". This will display the version of Node.js that has been installed on your machine. If you see the version number, it means that Node.js has been installed successfully.

Conclusion

In this blog post, we went through a step-by-step guide on how to install Node.js on a Windows machine. By following these steps, you should be able to install Node.js without any issues. Once you have installed Node.js, you can start building server-side applications using JavaScript.

 

Duplicated Products | C# | HackerRank

ISet<string> uniqueProducts = new HashSet<string>();

for(int i = 0; i < name.Count; i++)

{

    uniqueProducts.Add(name[i] + " " + price[i] + " " + weight[i]);

}

return name.Count = uniqueProducts.Count; 

Frequency of Max Value | C# | HackerRank

public static List<int> FrequencyOfMaxValue(List<int> numbers,

    List<int> q)

{

    List<int> result = new List<int>();

    int n = numbers.Count;

    int[,] table = new int[2,n];

    Dictionary<int, int> counts = new Dictionary<int, int>();

    table[0,n-1] = numbers[n-1];

    table[1,n-1] = 1;

    counts.Add(numbers[n-1], 1);

    for(int i = n-2; i >= 0; i--)

    {

        if(!counts.ContainsKey(numbers[i]))

            counts.Add(numbers[i],1);

        else

            counts[numbers[i]]++;

        if(numbers[i] > table[0, i+1])

        {

            table[0,i] = numbers[i];

            table[1,i] = 1;

        }

        else

        {

            table[0,i] = table[0, i+1];

            table[1,i] = counts[table[0,i]];

        }

    }

    for(int i = 0; i < n; i++)

    {

        result.Add(table[1,q[i] - 1]);

    }

    return result;

} 

Equal Levels | HackerRank

public static int updateTimes(List<int> signalOne,

     List<int> signalTwo)

{

    int noOfUpdate = 0;

    int maxEqual = int.MinValue;

    int length;

    int signalOneCount = signalOne.Count;

    int signalTwoCount = signalTwo.Count;

    if(signalOneCount < signalTwoCount)

        length = signalOneCount;

    else

        length = signalTwoCount;

    for(int i = 0; i < length; i++)

    {

        if(signalOne[i] == signalTwo[i])

        {

            if(maxEqual < signalOne[i])

            {

                maxEqual = signalOne[i];

                noOfUpdate++;

            }

        }

    }

    return noOfUpdate;

} 

Customer List | HackerRank Certification | React

 import React, {useState} from "react";

import "./index.css";

function CustomerList(){

    const[customer, setCustomer] = useState("");

    const[customers, setCustomers] = useState([]);

    const handleSubmit = e => {

        e.preventDefault();

        if(customers.length === 0)

            return;

        setCustomers([...customers,

            {name:customer, count:customer.length}]);

        setCustomer("");

    }

    let rendered = "";

    if(customer.length !== 0){

        rendered = <ul className="styled mt-50"

                        data-testid="customer-list">

                        {customers && customers.map(cus => {

                         return(

                           <li className="slide-up-fade-in"

                            data-testid={"list-item"+cus.count}

                            key={"list-item"+cus.count}>

                            {cus.name}

                           </li>

                         )

                        })}

                    </ul>

    }

    return(

        <div className="mt-75 layout-column

            justify-content-center

            align-items-center">

            <section className="layout-row

                align-items-center

                justify-content-center">

                <input type="text"

                    className="large"

                    placeholder="Name" data-testid="app-input"

                    value={customer}

                    onChange={e => setCustomer(e.target.value)} />

                <button type="submit"

                    className="ml-30"

                    data-testid="submit-button"

                    onClick={handleSubmit}>

                    Add Customer

                </button>

            </section>

            {rendered}

        </div>

    );

}

export default CustomerList

Count String Permutations | HackerRank Certification

Count all possible N-length vowel permutations that can be generated based on the given conditions

Given an integer N, the task is to count the number of N-length strings consisting of lowercase vowels that can be generated based the following conditions:

• Each ‘a’ may only be followed by an ‘e’.
• Each ‘e’ may only be followed by an ‘a’ or an ‘i’.
• Each ‘i’ may not be followed by another ‘i’.
• Each ‘o’ may only be followed by an ‘i’ or a ‘u’.
• Each ‘u’ may only be followed by an ‘a’.a

nput: N = 1
Output: 5
Explanation: All strings that can be formed are: “a”, “e”, “i”, “o” and “u”.

Input: N = 2
Output: 10
Explanation: All strings that can be formed are: “ae”, “ea”, “ei”, “ia”, “ie”, “io”, “iu”, “oi”, “ou” and “ua”.

using System;

using System.Collections.Generic;

class StringPermutation {

   

    static int countVowelPermutation(int n)

    {

   

        int MOD = (int)(1e9 + 7);

        long[,] dp = new long[n + 1, 5];

        for (int i = 0; i < 5; i++) {

            dp[1, i] = 1;

        }

        List<List<int>> relation = new List<List<int>>();

        relation.Add(new List<int> { 1 });

        relation.Add(new List<int> { 0, 2 });

        relation.Add(new List<int> { 0, 1, 3, 4 });

        relation.Add(new List<int> { 2, 4 });

        relation.Add(new List<int> { 0 });

        for (int i = 1; i < n; i++)

        {

            for (int u = 0; u < 5; u++)

            {

                dp[i + 1, u] = 0;

                foreach(int v in relation[u])

                {

                    dp[i + 1, u] += dp[i, v] % MOD;

                }

            }

        }

        long ans = 0;

        for (int i = 0; i < 5; i++)

        {

            ans = (ans + dp[n, i]) % MOD;

        }

        return (int)ans;

    }

    static void Main() {

        int N = 2;

        Console.WriteLine(countVowelPermutation(N));

    }

}

Condensed List | HackerRank Certification | Remove repeated node from a Singly Linked List

 Given a list of integers, remove any nodes that have values that have previously occurred in the list and return a reference to the head of the list.   

For e.g: 

Linked List

Input : 3 --> 4 --> 3 --> 6

Output: 3 --> 4 --> 6 

public static SinglyLinkedListNode(SinglyLinkedListNode head)

{

    var hSet = new HashSet<int>();

    SinglyLinkedListNode newList = new SinglyLinkedListNode();

    while(head != null)

    {

        hSet.Add(head.data);

        head = head.next;

    }

    foreach(int i in hSet)

    {

        newList.InsertNode(i);

    }

    return (newList.head);

}