After winning gold and silver in Indian Computing Olympiad 2014, Arun Gupta and Mani Iyer want to have some fun.
Now they are playing a game on a grid made of n horizontal and m vertical sticks.
An intersection point is any point on the grid which is formed by the intersection of one horizontal stick and one vertical stick.In the grid shown below,n = 3 and m = 3. There are n+m= 6 sticks in total. There are nm = 9 intersection points, numbered from 1 to 9.
The rules of the game are very simple. The players move in turns. Arun Gupta won gold, so he makes the first move.
During his/her move, a player must choose any remaining intersection point and remove from the grid all sticks which pass through this point.
A player will lose the game if he cannot make a move (i.e. there are no intersection points remaining on the grid at his move).
Assume that both players play optimally. Who will win the game?
Input Format:
The first line of input contains two space-separated integers,n, and m(1 ?n,m? 100).
Output Format:
Print a single line containing "Arun Gupta" or "Mani Iyer" (without the quotes), depending on the winner of the game.
Sample Input 1:
2 2
Sample Output 1:
Mani Iyer
Sample Input 2:
2 3
Sample Output 2:
Mani Iyer
Sample Input 3:
3 3
Sample Output 3:
Arun Gupta
Solution:
#include<iostream>
using namespace std;
int main()
{
int n, m, res;
cin >> n >> m;
if(n < m)
{
res = n;
}
else
{
res = m;
}
if(res % 2 == 0)
{
cout << “Mani Iyer”;
}
else
{
cout << “Arun Gupta”;
}
return 0;
}
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